<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom">
  <channel>
    <title>Generate a Normal Distribution on Sulprobil</title>
    <link>https://www.sulprobil.de/tags/generate-a-normal-distribution/</link>
    <description>Recent content in Generate a Normal Distribution on Sulprobil</description>
    <generator>Hugo</generator>
    <language>en</language>
    <lastBuildDate>Wed, 10 Jun 2026 16:20:00 +0100</lastBuildDate>
    <atom:link href="https://www.sulprobil.de/tags/generate-a-normal-distribution/index.xml" rel="self" type="application/rss+xml" />
    <item>
      <title>sbGenNormDist (VBA)</title>
      <link>https://www.sulprobil.de/sbgennormdist_en/</link>
      <pubDate>Wed, 10 Jun 2026 16:20:00 +0100</pubDate>
      <guid>https://www.sulprobil.de/sbgennormdist_en/</guid>
      <description>&lt;h2 id=&#34;abstract&#34;&gt;Abstract&lt;/h2&gt;&#xA;&lt;p&gt;To generate a standard normal distribution you can use &lt;em&gt;=NORM.S.INV(RAND())&lt;/em&gt;.&#xA;If you need a normal distribution with a mean of 7 and a standard deviation&#xA;of 10 then use &lt;em&gt;=NORM.INV(RAND(),7,10)&lt;/em&gt;.&lt;/p&gt;&#xA;&lt;p&gt;But: Your normal distribution will&#xA;never show a mean of exactly 7 (and a standard deviation of exactly 10) unless&#xA;the number of draws approaches infinity. If you want to ensure a mean of 7&#xA;and a standard deviation of 10 then shift an originally generated series of&#xA;random numbers to this mean and zoom it to the required standard deviation.&#xA;You can achieve this with at least three different approaches:&lt;/p&gt;</description>
    </item>
  </channel>
</rss>
